How Is Minimum Sensitivity Calculated in Instruments?

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Homework Help Overview

The discussion revolves around the calculation of minimum sensitivity in instruments, specifically focusing on the relationship between output voltage and the measured quantity, which in this case is displacement.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of sensitivity and its calculation, with one suggesting the use of derivatives to find the rate of change of voltage with respect to distance. Questions arise regarding the choice of input value and whether to consider the absolute value of sensitivity.

Discussion Status

Participants are actively questioning assumptions about the definitions and calculations involved in determining sensitivity. Some guidance has been offered regarding the interpretation of sensitivity as a rate of change, and there is an exploration of different input values to assess their impact on sensitivity.

Contextual Notes

There is a discussion about the appropriateness of using a specific displacement value (5.0 mm) for calculating sensitivity, as well as considerations regarding the sign of the sensitivity value.

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Homework Statement
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The attempt at a solution
First, we define sensitivity as the change of an instrument or transducer's output per unit change in the measured quantity.

So to find the minimum sensitivity I simply plugged in the largest possible input (5.0 mm) into the equation:

E = 9.5e-0.4(5.0)

E = 1.286 V

Is this correct?
 
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I would say no, that is in fact the "minimum voltage" you would expect to occur

I would associate sensitivity with rate of change of voltage with distance
 


So I would first have to take the derivative, and then plug in 5.0?

Doing this I would get an answer of -0.514 V/mm. So will my final answer be 0.514 V/mm, if I were to take the absolute value?
 
Last edited:


if you can explain why you choose 5 (which is a reasonable choice), it sounds like a plan
 


I chose a displacement of 5.0 mm because it will give me the smallest rate of change, whereas if I chose a number closer to 0, I would get a higher rate of change, which means higher sensitivity.

Also, do I keep the value negative, or take the absolute value? I don't think negative sensitivity makes sense.
 


may have to check you notes, it may be defined as the magnitude of rate of change as you're hinting
 

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