How Is Momentum Conserved in Different Collision Scenarios?

Click For Summary
SUMMARY

This discussion focuses on the conservation of momentum in various collision scenarios, specifically addressing three questions related to explosive events and collisions. In Question 1, the correct answer is determined to be option d, as the vector sum of the linear momenta of the fragments must be zero due to the conservation of momentum in a system with no external forces. For Question 2, option c is identified as correct, indicating that the smaller fragment must have twice the speed of the larger fragment to conserve momentum. Question 3 requires analyzing momentum in both x and y directions to determine the final direction of Car 2 after the collision.

PREREQUISITES
  • Understanding of momentum (p = mv) and impulse (Impulse = force * time = change in momentum)
  • Knowledge of elastic and inelastic collisions
  • Familiarity with vector analysis in physics
  • Basic principles of explosions and conservation laws in physics
NEXT STEPS
  • Study the principles of elastic vs. inelastic collisions in detail
  • Learn about vector decomposition and how to analyze momentum in multiple dimensions
  • Explore the concept of impulse and its relationship with momentum conservation
  • Review case studies of explosive events and their momentum implications
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and momentum conservation, as well as educators looking for examples of collision scenarios and explosive dynamics.

Nano
Messages
33
Reaction score
0

Homework Statement



QUESTION 1 :A stationary bomb explodes in space breaking into a number of small fragments. At the location of the explosion, the net force do to gravity is 0 Newtons. Which one of the following statements concerning the event is true?
a) Kinetic energy is conserved in the process
b) The fragments must have equal kinetic energies
c) The sum of the KE's of the fragments must be 0
d) The vector sum of the linear momenta of the fragments must be zero
e) The velocity of anyone fragment must be equal to the velocity of any other fragment

QUESTION 2 : An object of mass 3m, initially at rest, explodes breaking into two fragments of mass m and 2m respectively. Which of the statements is true (after the explosion)?
a) They may fly off at right angles
b) They may fly off in the same direction
c) The smaller fragment will have twice the speed of the larger fragment
d) The larger fragment will have twice the speed of the smaller fragment
e) the smaller fragment will have four times the speed of the larger fragment

QUESTION 3: Car one is traveling due north and Car Two is traveling due east. After the collision shown, Car 1 rebounds due south. Which of the numbered arrows is the only one that can represent the final direction of Car 2.
Arrow 1 - 180 degrees
Arrow 2 - 150 degrees
Arrow 3 - 90 degrees
Arrow 4 - 30 degrees
Arrow 5 - 0 degrees

Homework Equations



p = mv
Impulse = force * time = change in momentum

The Attempt at a Solution



QUESTION 1 : Its obviously not an elastic collision because kinetic energy is lost in the explosion--which rules out a. Kinetic energy is always positive, so the sum can't be zero--not c. I don't understand b or e. I think its d, because momentum has to be conserved.
QUESTION 2 : I think its c, because momentum must be conserved and that is the only way that both fragments have a momentum of 2ms after the collision
QUESTION 3: I have no idea how to solve this problem. How can you find the direction of final velocity without pluggin in numbers?
 
Physics news on Phys.org
The first 2 look OK.

The third one, wants you to conserve momentum in both x and y.

Before the collision you had +Y and -X momentum, after you have some -Y and ...
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 41 ·
2
Replies
41
Views
12K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 71 ·
3
Replies
71
Views
5K