How is reflectivity of a surface determined?

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The reflectivity of a surface can be determined using Fresnel's equations, which derive from Maxwell's equations. The reflection coefficient, represented by gamma (Γ), is calculated using the indices of refraction of the two media involved, typically air and glass. The incident and reflected powers are related through the equation P(reflected) = Γ² P(incident). While indices of refraction are well-documented, calculating them without physical testing is challenging, particularly for amorphous materials.

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  • Understanding of Fresnel's equations
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I have no real experience in this subject and wanted to ask, can the amount of reflection (in terms of electromagnetic waves) of a substance be determined without physical testing?
 
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Yup, the reflectivity of an interface can be expressed through Fresnel's equations... which are from Maxwell's equations:

Just FYI (for normal incidence):

\Gamma = \frac{n_1 - n_2}{n_2 + n_1}

where gamma represents the reflection coefficient.
 
Last edited:
Ummmmm...
What do you plug in for n1 & n2
 
The index of refraction of medium 1 (original) and medium 2 (new). Usually air is n1 and n2 is glass.

Incident and reflected powers
P(reflected) = \Gamma^2 P(incident)
 
Oh. Actually I was wondering how you determine refractive index without testing. Sorry.
 
The indices of refraction of optical materials are well tabulated.
 
Last edited:
The index or refraction is the ratio of the speed of light in a vacuum to the speed in the medium. To find the speed in the medium you need the materials relative permeability and permittivity. And that is found by measurment. Permeability and permittivity of a vacuum come from Maxwell's equations.

Regards
 
One can calculate optical properties ab initio (with band structure calculations) but it is difficult to get good agreement with experiment.
 
  • #10
What is the material?
If you have a crystalline structure, yes, calculate using the band structure all of the material poperties you want. As Pieter has said, you will have great difficulties getting agreement with experimental evidence.

If the material is amorphous, like a glass, lots of luck. I am not an amorphous material expert, but I'd be very suprised if you can get an answer in general.

dt
 

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