How is the amplitude of a wave related to the slit width?

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Homework Help Overview

The discussion revolves around the relationship between the amplitude of a wave and the width of a slit, particularly in the context of wave behavior in diffraction scenarios. Participants explore how varying the slit width affects the amplitude while keeping the slit separation constant.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants discuss the proportionality between amplitude and slit width, with some attempting to clarify the underlying reasons for this relationship. Questions arise regarding the implications of slit width on intensity and how amplitude is derived from slit segments in diffraction calculations.

Discussion Status

The discussion is active, with participants engaging in clarifying questions and exploring different interpretations of the relationship between amplitude and slit width. Some guidance on the proportionality of amplitude to slit width has been suggested, but there is no explicit consensus on the reasoning behind it.

Contextual Notes

There is mention of potential ambiguity in the original question regarding 'slit separation' and its relevance to the intensity of the central maximum in a Young's double slit experiment. This indicates that some foundational assumptions may need further examination.

Faiq
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Homework Statement


How is the amplitude of a wave affected if the slit separation remains same but slit width is
1.)Increased?
2.)Decreased?
and why?

Homework Equations


Intensity is proportional to the square of amplitude

The Attempt at a Solution


I consider the amplitude as allowed "fatness" of a wave. The more slit width there is, the more wave can be "fat" and so it will have a greater amplitude.
 
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As you wrote intensity is proportional to the square of amplitude.
Do you know the relation between intensity of wave and the width of slits?
The intensity of light due to a slit (source of light) is directly proportional to width of the slit.
Therefore if the two slits ##S_1## & ##S_2## have widths ##W_1## & ##W_2## respectively and ##I_1## & ##I_2## are intensities of light waves having amplitude ##a_1## and ##a_2## from respective slits then,

##\frac{I_1}{1_2}## ∝ ##\frac{a_1^2}{a_2^2}## ∝ ##\frac{W_1}{W_2}##
 
Yes, I know that. I am asking why does the amplitude increases with increasing slit width
 
Faiq said:
Yes, I know that. I am asking why does the amplitude increases with increasing slit width
In single slit diffraction calculations, the resultant amplitude is obtained by dividing the slit width into a large number of equal segments. For each segment, the amplitude is taken proportionally equal and the resultant amplitude is found by superposition of amplitudes of all the segments at the point of consideration.
So amplitude should be proportional to slit width.
 
diffraction.png


Can you see division of the slit width into a large number of equal segments?
 
Was my answer helpful?
 
Then (amplitude)^2 is proportional to slit width or it is amplitude proportional to slit width??
 
The amplitude of the wave passing through a slit is directly proportional to its width. If the slit width is x and amplitude of the wave is A, then A ∝ x.
 
HI @ube. For information, you are replying to a very old (April 2016) thread.

Note, the original question is unclear/incomplete. The Homework Statement refers to 'slit separation' - I would guess the question is actually about the intensity of the central maximum in a Young's double slit experiment.

If you have your own question, your best bet is to post a new thread and include your own attempt/reasoning at the answer.

Edit - typo' corrected.
 
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