How is the Catenary Equation Derived?

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Homework Help Overview

The discussion revolves around the derivation of the catenary equation, specifically the mathematical representation given by x = t and y = a*cosh(t). Participants are seeking insights and resources to better understand this concept.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants express curiosity about the derivation process and seek resources for deeper understanding. Some suggest looking into statics books for comprehensive explanations, while others share links to various online resources, noting their limitations in providing a clear derivation.

Discussion Status

The discussion is ongoing, with participants sharing links and resources. There is an acknowledgment of the complexity of the topic, and while some guidance has been provided, no consensus on a definitive explanation has been reached.

Contextual Notes

Participants mention that the resources shared do not fully explain the derivation, indicating a potential gap in available materials. There is also a suggestion to consult specific textbooks for more thorough insights.

amcavoy
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I am curious as to how the equation of a catenary was derived:

x = t
y = a*cosh(t)

Does anyone have any insight on this or know a good webpage that can explain it?

Thank you for the assistance.
 
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Here's the most in depth I could find:

http://www.kmlhs.org/faculty/TKUEHL/Precalculus/MESA/Arch/Arch%20History.htm
 
Last edited by a moderator:
Its long and complicated. I would get a nice statics book to show you the solution.


http://planetmath.org/encyclopedia/ChainCurve.html

(Link really does not show you how anything is derived though)

http://www.whim.org/nebula/math/catenary.html

(again not great)

Go get yourself Statics by RC Hibbeler, and Ill help you if u are stuck.
 
Last edited by a moderator:
Thanks for the links. I actually found something almost identical to the material on the Planetmath site (it also had a picture, though). For now, I think something like that is sufficient (although I'm sure I'll come across it in a future class). Thanks again...
 

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