Erika Martin Messages 1 Reaction score 0 Thread starter Feb 18, 2008 #1 How is derived the classical energy-momentum relation, E = p^2/2m? Thanks!
lavalamp Messages 278 Reaction score 1 Feb 18, 2008 #2 Kinetic Energy = [tex]0.5 * mv^{2}[/tex] momentum = p = mv Kinetic Energy = [tex]0.5 * p * v[/tex] Kinetic Energy = [tex]0.5 * p * p/m[/tex] Kinetic Energy = [tex]0.5 * p^{2}/m[/tex] Kinetic Energy = [tex]p^{2}/2m[/tex]
Kinetic Energy = [tex]0.5 * mv^{2}[/tex] momentum = p = mv Kinetic Energy = [tex]0.5 * p * v[/tex] Kinetic Energy = [tex]0.5 * p * p/m[/tex] Kinetic Energy = [tex]0.5 * p^{2}/m[/tex] Kinetic Energy = [tex]p^{2}/2m[/tex]