How is the equation given for v_b tangent to it?

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SUMMARY

The discussion centers on the analysis of the tangent velocity vector v_b in the context of circular motion. The participant initially misunderstands v_b as a radius vector rather than recognizing it as the instantaneous velocity vector that is perpendicular to the radius. The clarification provided indicates that at position B, the velocity vector has equal horizontal and vertical components, confirming its tangential nature. This understanding resolves the confusion regarding the relationship between the radius and the tangent vector in circular motion.

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Homework Statement



I'm trying to follow a solved example in the book. I understand everything except one "trivial" (for most of you) analysis of the tangent velocity vector v_b. Because v_b is unknown it is written as its magnitude times the direction it follows constrained in a circular path.

However, my understanding of v_b written as in the picture followed is not tangent. That is the vector that describes the radius of the path, and not the perpendicular to the radius which will be the instantaneous velocity.


Homework Equations


Please see attached picture


The Attempt at a Solution


how is the equation given for v_b tangent to it? this is the vector describing the radius of the path?

Thank you
 

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That right triangle with sides 1 and 1, on the radius of the circular path, indicates that at the current position B is constrained to moving as much to the right as upwards, per unit of time, meaning a velocity vector having equal horiz and vertical components, at the instant represented.
 
Thank you, makes sense now. Wish I'd asked earlier.
 

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