How is the following fraction split for inverse Fourier?

[Jeviah]

Hi i’m having problems with the following equations:

X(w)=2/(-1+iw)(-2+iw)(-3+iw)

This then becomes the following equation according the the tutorial, although there is no explanation as to how:

X(w)=1/-1+iw, -2/-2+iw, +1/-3+iw

The commas indicated the end of each fraction to make it easier to interpret

This process is for inverse Fourier transform which i understand however to do not understand how the above step was completed

 

[vela]

Use partial fractions.

 

[Jeviah]

Thank you i figured it out, although i have a problem with another question if you could possibly help out please

6/(2iw-3)^2(iw+1)
I have split it and obtained B=12/5 and C=6/12 with the layout A/(2iw-3), +B/(2iw-3)^2, +C/(iw+1) cancelling them out of the original equation to obtain the respective values

How would i obtain A considering using the cancellation method above, the denominator would equal 0