How Is the Force on a Helium Ion Calculated in a Magnetic Field?

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The force on a He2+ ion in a magnetic field is calculated using the formula F=qvbsinθ. For a helium ion traveling at a velocity of 1.3 × 10^5 m/s in a magnetic field of 0.42 T, the charge is confirmed to be 2 times the elementary charge, or 2*1.6e-19 C. The calculation for the force yields F=2*1.6e-19*1.3e5*0.42. Understanding the charge of the helium ion is crucial for accurate force computation. The discussion clarifies that the charge is indeed 2*1.6e-19 C.
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Homework Statement


What is the magnitude of the force experienced by a He2+ ion traveling with v = 1.3 × 10^5i m/s in a magnetic field B = 0.42 j T?

Homework Equations


F=qvbsinθ

The Attempt at a Solution


F=2*1.6e-19*1.3e5*0.42

I am unsure about the charge on the Helium ion.

Is it 2*1.6e-19?
 
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Imagine a neutral He atom. Now strip off all the electrons. What is left? Two neutrons and two protons, so...
 
Geofleur said:
Imagine a neutral He atom. Now strip off all the electrons. What is left? Two neutrons and two protons, so...

So the charge is 2*1.6e-19?
 
Yep.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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