How Is the Force on a Helium Ion Calculated in a Magnetic Field?

In summary, the basic force on a charged particle in a magnetic field is called the Lorentz force, which is perpendicular to both the direction of the magnetic field and the direction of motion of the particle. The magnitude of the force is determined by the charge of the particle, the strength of the magnetic field, and the velocity of the particle. The direction of the force can change depending on the direction of the magnetic field and the velocity of the particle. The force is responsible for the circular motion of the particle, with the radius of the circular motion being directly proportional to the velocity and the magnetic field strength, and inversely proportional to the mass and magnitude of the charge. The direction of the magnetic field can affect the motion of a charged
  • #1
Mnemonic
21
0

Homework Statement


What is the magnitude of the force experienced by a He2+ ion traveling with v = 1.3 × 10^5i m/s in a magnetic field B = 0.42 j T?

Homework Equations


F=qvbsinθ

The Attempt at a Solution


F=2*1.6e-19*1.3e5*0.42

I am unsure about the charge on the Helium ion.

Is it 2*1.6e-19?
 
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  • #2
Imagine a neutral He atom. Now strip off all the electrons. What is left? Two neutrons and two protons, so...
 
  • #3
Geofleur said:
Imagine a neutral He atom. Now strip off all the electrons. What is left? Two neutrons and two protons, so...

So the charge is 2*1.6e-19?
 
  • #4
Yep.
 

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