How is the UTS different from breaking stress and why?

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SUMMARY

The Ultimate Tensile Strength (UTS) is defined as the maximum stress a material can withstand before failure, while breaking stress refers to the stress at the point of rupture. The engineering stress-strain curve assumes a constant cross-sectional area, leading to a peak stress value at UTS, after which stress appears to decrease due to necking. In contrast, the true stress-strain curve accounts for the reduction in cross-sectional area, showing that true stress continues to rise until rupture. Understanding these distinctions is crucial for material science and engineering applications.

PREREQUISITES
  • Understanding of engineering stress-strain curves
  • Familiarity with true stress-strain concepts
  • Knowledge of material yield points and necking phenomena
  • Basic principles of Hooke's Law and its limitations
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  • Study the differences between engineering stress and true stress in material testing
  • Explore the implications of necking on material failure
  • Learn about the stress-strain behavior of different materials, such as steel and aluminum
  • Investigate advanced material testing techniques beyond standard tensile tests
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Materials engineers, mechanical engineers, and students studying material science who seek to deepen their understanding of material failure mechanisms and stress analysis.

Tangeton
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By definition the UTS is the maximum stress a material can take. But how exactly can a material not break after reaching the UTS if it is so? Why is there a breaking stress and how come on the graph of stress against strain the stress seems to decreases before the braking stress?
 
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Tangeton said:
By definition the UTS is the maximum stress a material can take. But how exactly can a material not break after reaching the UTS if it is so? Why is there a breaking stress and how come on the graph of stress against strain the stress seems to decreases before the braking stress?
There is an engineering stress strain curve and a true stress strain curve. The engineering stress strain curve assumes that the member cross section area remains constant at all levels of tensile load, but in actuality, cross section starts to significantly reduce (called necking) at high stress values beyond the yield point, in which case if you plot true stress, which accounts for the reduced cross section area , versus strain, the true stress value always increases up to rupture, whereas if you use engineering stress, you get a peak on the curve prior to significant necking, and beyond that, the stress gets lower because it is assumed that cross section remains constant . The value of the engineering stress at this peak is called the ultimate tensile strength, whereas the breaking strength is the rupture stress at point of failure .
 
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PhanthomJay said:
There is an engineering stress strain curve and a true stress strain curve. The engineering stress strain curve assumes that the member cross section area remains constant at all levels of tensile load, but in actuality, cross section starts to significantly reduce (called necking) at high stress values beyond the yield point, in which case if you plot true stress, which accounts for the reduced cross section area , versus strain, the true stress value always increases up to rupture, whereas if you use engineering stress, you get a peak on the curve prior to significant necking, and beyond that, the stress gets lower because it is assumed that cross section remains constant .

I understand the point you're trying to make about cross-sectional section remaining constant, but since Stress = F/A, if A is constant, should stress be still increasing with the force applied? I know that it is a stress vs strain graph, but strain is extension over length and the bigger the extension, the larger the force from Hooke's law, so the force must be increasing with stress it would seem to me?
 
Tangeton said:
I understand the point you're trying to make about cross-sectional section remaining constant, but since Stress = F/A, if A is constant, should stress be still increasing with the force applied? I know that it is a stress vs strain graph, but strain is extension over length and the bigger the extension, the larger the force from Hooke's law, so the force must be increasing with stress it would seem to me?
But Hooke's Law does not apply after yielding, since the stress strain curve is no longer linear beyond the yield stress ( we're talking steel or aluminum as an example), and thus, increasing strain no longer implies increasing force. Ideally, when you apply an increasing tensile load to a test specimen, the elongation and strain increase as the applied load increases until yield, but then the elongation increases without much increase in the applied load, sort of like silly putty where stretching becomes extensive with no increase in applied load required.
 
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