How Is the Volume of a Spherical Segment Calculated Using Cavalieri's Principle?

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Cavalieri's Principle can be applied to find the volume of a spherical segment by comparing it to a cone and half-sphere configuration. The volume of the half-sphere is calculated as 2/3πr², while the volume of the cone that fits within it is 1/3πr². The challenge lies in determining the relationship between the spherical segment's height (h) and the sphere's radius (r). The discussion indicates difficulty in deriving the volume formula, particularly when trying to relate the cone's dimensions to the spherical segment. Understanding the geometric relationships and applying Cavalieri's Principle correctly is essential for deriving the volume of the spherical segment.
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Homework Statement



Use Cavalieri's Principle to find the volume of a spherical segment of one base and thinckness h if the radius of the sphere is r.

Homework Equations



http://img395.imageshack.us/img395/2826/sphere1.jpg

Volume of half-sphere: 2/3\pir2
Volume of cone inverse to half-sphere: 1/3 \pir2

The Attempt at a Solution



I've been working this for the last three days and can't see how the answer is derived. The best I've been able to do is work out a cone with height and radius \alpha where \alpha= r-h

But I haven't had any success this way, and question its usefulness.

If need be, I can post what the answer is supposed to be, I'm just interested in how its derived.
 
Last edited by a moderator:
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navybuttons said:

Homework Statement



Use Cavalieri's Principle to find the volume of a spherical segment of one base and thinckness h if the radius of the sphere is r.

Homework Equations



http://img395.imageshack.us/img395/2826/sphere1.jpg

Volume of half-sphere: 2/3\pir2
Volume of cone inverse to half-sphere: 1/3 \pir2

The Attempt at a Solution



I've been working this for the last three days and can't see how the answer is derived. The best I've been able to do is work out a cone with height and radius \alpha where \alpha= r-h

But I haven't had any success this way, and question its usefulness.

If need be, I can post what the answer is supposed to be, I'm just interested in how its derived.

Le Cavalieris principle is about functions in the plane (2d) that are "hightened" into space (3d) by revolving them about the x-axis. A cut half circle would do here.
 
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