How Is the Work Done by Friction Calculated on an Inclined Plane?

[behzad82]

a 500 kg crate is on a rough surface inclined at 30°. A constant external force
P = 4000 N is applied horizontally to the crate. The force pushes the crate a distance of 3.0 m up the
incline, in a time interval of 9.2 s, and the velocity changes from ν1 = 1.0 m/s to ν2 = 2.8 m/s. The
work done by the friction force is closest to:

I have no idea how to start this. I tried just using the regular work equation or conservation of energy and did not find the answer.

 

[Bloodthunder]

You are posting this in the wrong forum.

Anyway, find the work done by the force, then find the work done to bring it from a lower to a higher region, to increase the velocity, etc. , and just minus off all of them to find the work done to overcome friction.