How is there no net force in this situation

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In the scenario of a man pushing a 190 kg piano down a 17-degree incline at constant velocity, the key point is that there is no net force acting on the piano, which implies that the applied force must balance the gravitational component acting parallel to the incline. Although friction is neglected, the normal force still exists, and the man must exert a force equal to the gravitational component to maintain constant velocity. The discussion emphasizes that if a net force were present, the piano would accelerate, contradicting the given condition of constant motion. To analyze the forces effectively, it's suggested to break them down into components parallel and perpendicular to the incline. Understanding these dynamics clarifies why the man's pushing force matches the gravitational pull along the incline.
Rasiel
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Homework Statement


[/B]
A man pushes on a piano with mass 190 kg ; it slides at constant velocity down a ramp that is inclined at 17.0 ∘ above the horizontal floor. Neglect any friction acting on the piano.

A. Calculate the magnitude of the force applied by the man if he pushes parallel to the incline.

Homework Equations


Sum of forces = maMy question is not regarding the solution. I'm aware that the solution is mgsin(theta) but my question is how come there is no acceleration, yet there is only one force in the positive x direction since it says there is no friction. And why does the man push exactly as hard as the component of gravity in the x direction? I can see where the answer comes from, just not why.
 
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There is a normal force from the ramp even if there is no friction.
 
I also can not figure out why the man has to push with a force equal to the component of weight. One insight though is that they have asked to neglect friction which does not mean friction is not present. If a net force is acting then it can not move with constant velocity.
 
Rasiel said:

Homework Statement


[/B]
A man pushes on a piano with mass 190 kg ; it slides at constant velocity down a ramp that is inclined at 17.0 ∘ above the horizontal floor. Neglect any friction acting on the piano.

A. Calculate the magnitude of the force applied by the man if he pushes parallel to the incline.

Homework Equations


Sum of forces = maMy question is not regarding the solution. I'm aware that the solution is mgsin(theta) but my question is how come there is no acceleration, yet there is only one force in the positive x direction since it says there is no friction. And why does the man push exactly as hard as the component of gravity in the x direction? I can see where the answer comes from, just not why.
What in the question statement tells you the direction of the applied force? I see no direction given other than that it's parallel to the incline...
 
Kajal Sengupta said:
One insight though is that they have asked to neglect friction which does not mean friction is not present.
It means you are supposed to treat the problem as if it was not present.

Kajal Sengupta said:
If a net force is acting then it can not move with constant velocity.

Exactly. So you need to figure out how hard the man has to push in order for there to be no net force. You have two unknowns, the magnitude of the normal force and the magnitude of the applied force. You need to make sure that all of the force components are zero and so you have two equations to determine your two unknowns.

Hint: It is easier if you consider the force equations in the direction parallel and perpendicular to the plane, respectively.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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