How is This Laplace Transform Rewritten for a Final Step?

[myusernameis]

Homework Statement

this is the last step to a laplace transform, but I'm stuck..
$$\frac{(3-2x)}{((s+3)²)+4}$$
to
-2$$\frac{(s+3)}{(((s+3)²)+4)}$$9/2 $$\frac{2}{((s+3)²)+4}$$


thanks

 

[tiny-tim]

Hi myusernameis!

(use ^ not SUP in LaTeX )

$$\frac{(3-2s)}{((s+3)^2)+4}$$

= $$\frac{(9 - 6 - 2s)}{((s+3)^2)+4}$$

= -2$$\frac{(s+3)}{(((s+3)^2+4)}$$ + 9/2 $$\frac{2}{((s+3)^2)+4}$$

 

[myusernameis]

Hi myusernameis!

(use ^ not SUP in LaTeX )

haha i used ^ but the laTeX gave me SUP..

thanks a bunch!