How is torque converted into propelling force on a vehicle?

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SUMMARY

The conversion of torque into propelling force in a vehicle is fundamentally governed by the friction force between the tire and the ground. The relationship is defined by the equation: Wheel Torque = Friction Force X Tire Radius. Static friction initiates motion by inducing acceleration, while the conditions for wheel slipping are determined by the friction coefficient. When designing an engine, the torque required to propel a vehicle can be calculated using the formula: Vehicle Acceleration = Wheel Torque / Tire Radius / Vehicle Mass, assuming negligible drag forces.

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  • Understanding of basic physics concepts, particularly Newton's laws of motion.
  • Familiarity with the concepts of torque and friction.
  • Knowledge of vehicle dynamics, including mass and acceleration relationships.
  • Basic grasp of tire mechanics and their interaction with road surfaces.
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  • Research the physics of static and kinetic friction, focusing on the friction coefficient.
  • Study the principles of vehicle dynamics, particularly longitudinal acceleration.
  • Explore the relationship between torque, wheel radius, and vehicle propulsion.
  • Learn about the design considerations for engines in relation to vehicle mass and required acceleration.
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Automotive engineers, physics students, vehicle dynamics researchers, and anyone involved in vehicle design and performance optimization.

koolraj09
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Hi all.
I didn't get it cleared although i tried searching the internet.
1) Firstly, how does a vehicle gets off...i mean how the torque is converted into propelling force. I don't want to know the mechanism, gears etc...i want to know the physics...
2) Another question is that whether static friction force is itself the propelling force in this case? And how the friction force varies from the start. Like at t=0, friction force is totally static. Then how does it proceed on.
3) Also what is the condition when wheels start slipping?
4) If I were to design an engine how would I decide what's the torque of engine to propel a vehicle of say mass 'm' and acceleration 'a'
Just for simplification i assume that at low speeds the drag force is negligible.
5) Lastly, what's the difference between the terms traction, tractive force and tractive effort?
I Googled but everyone has different things to say about it! And is tractive force equal to [mass x acceleration] of the vehicle? or is it equal to the static friction force. I'm totally confused over this topic. Please, help required.
Thanks in advance.
 
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Hey guys...no reply??
Atleast suggest something!
 
Draw yourself a FBD of a tire subject to a weight force down, a normal force upward from the pavement, a friction force from the pavement, a reaction force on the axle, and a torque on the axle. Then write the equations of motion for the tire. This should give you an idea about where the force driving the car forward comes from.
 
koolraj09 said:
1) Firstly, how does a vehicle gets off...i mean how the torque is converted into propelling force. I don't want to know the mechanism, gears etc...i want to know the physics...

The propelling force is the friction force between the tire and the ground. The relationship between the torque and the friction force is Wheel Torque = Friction Force X Tire Radius.

koolraj09 said:
2) Another question is that whether static friction force is itself the propelling force in this case? And how the friction force varies from the start. Like at t=0, friction force is totally static. Then how does it proceed on.

The friction force induces an acceleration to the vehicle, which increases its velocity and then initiate motion. I'm not sure if this answers your question.

koolraj09 said:
3) Also what is the condition when wheels start slipping?

See Sources >> Friction coefficient at the bottom of this page.

koolraj09 said:
4) If I were to design an engine how would I decide what's the torque of engine to propel a vehicle of say mass 'm' and acceleration 'a'
Just for simplification i assume that at low speeds the drag force is negligible.

See Theory >> Longitudinal acceleration >> Accelerating at the bottom of this page. The general case is equation (5b) where you could replace the friction force (Ft) with Wheel Torque / Tire Radius as seen previously. So, assuming no aerodynamics forces or rolling resistance:

Vehicle Acceleration = Wheel Torque / Tire Radius / Vehicle Mass

koolraj09 said:
5) Lastly, what's the difference between the terms traction, tractive force and tractive effort?
I Googled but everyone has different things to say about it! And is tractive force equal to [mass x acceleration] of the vehicle? or is it equal to the static friction force.

All of these terms are related to the tire friction force.
 
Thanks all! I think i got it.
 

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