How Is Work Calculated for a Driver Plate During Stress Accumulation?

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Show that the work done by the driver plate during a stress accumulation phase is W=[itex]\frac{2m<sup>2</sup>g<sup>2</sup>f<sub>d</sub>}{k}[/itex](fs-fdI'm not sure where to start with this. I am given several equations but can't reach the desired equation.
Fn=ρghA
m=ρA3/2
θ=[itex]\frac{f<sub>s</sub>}{f<sub>d</sub>}[/itex]
X=[itex]\frac{xG}{2f<sub>s</sub>ρghA<sup>1/2</sup>}[/itex]
U=[itex]\frac{u}{f<sub>s</sub>gh}[/itex]([itex]\frac{G}{2ρ}[/itex])1/2

Homework Statement


Homework Equations


The Attempt at a Solution

 
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The work done by the driver plate during a stress accumulation phase is given by W = Fs*X, where Fs is the force exerted by the driver plate and X is the displacement of the driver plate. Using the equations given, we can rewrite Fs as Fn/θ and X as U*(G/(2ρ))1/2. Therefore, we can calculate the work done during a stress accumulation phase as follows:W = \frac{Fn}{θ} * U * \frac{G}{2ρ})1/2= \frac{ρghA}{θ} * \frac{u}{fsgh} * \frac{G}{2ρ})1/2= \frac{2m2g2fd}{k}(fs-fd