How long does it take for a stone thrown from a bridge to hit the water below?

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SUMMARY

The discussion revolves around calculating the time it takes for a stone thrown upwards at 30 m/s from a height of 210 m to hit the water below. The equations of motion used include the velocity equation v = -9.8t + 30 and the height equation h = -4.9t² + 30t + 210. The key conclusion is to solve for the time when the height h equals zero, indicating the moment of impact with the water.

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Nitrate
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Homework Statement


A stone is thrown up at 30 m/s from the edge of a bridge 210 m above the river below. How many seconds elapse between toss and splash?



Homework Equations





The Attempt at a Solution


dv/dt=-9.8
v=-9.8t+c2
30=-9.8(0) + c1
c1=30

v=-9.8t+30
h=-4.9t^2+30t+c2
210=-4.9(0)^2+30(0)+c2
c2=210
h= -4.9t^2+30t+210

i'm not sure if I'm doing this right/what to do next if i am
 
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Nitrate said:

Homework Statement


A stone is thrown up at 30 m/s from the edge of a bridge 210 m above the river below. How many seconds elapse between toss and splash?



Homework Equations





The Attempt at a Solution


dv/dt=-9.8
v=-9.8t+c2
30=-9.8(0) + c1
c1=30

v=-9.8t+30
h=-4.9t^2+30t+c2
210=-4.9(0)^2+30(0)+c2
c2=210
h= -4.9t^2+30t+210

i'm not sure if I'm doing this right/what to do next if i am

Yes, your last equation looks okay to me. You've defined h=o at the surface of the water, which is fine. Solve for the time it takes for h to reach 0...
 

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