How Long Does It Take for an Object to Fall to the Ground?

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Discussion Overview

The discussion revolves around the question of how long it takes for an object to fall to the ground when dropped from a certain height, assuming no frictional forces and that it is on Earth. Participants explore the relationship between height, time, and velocity in the context of free fall.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • James asks if the time to hit the ground can be determined given only the height of the object, assuming no friction.
  • Another participant questions whether the final velocity is unknown and states that the initial velocity is zero.
  • One participant explains that the height is the distance between the object and the floor and presents the equation for free fall, stating that time can be calculated using \( t = \sqrt{\frac{2h}{g}} \) and that the initial velocity is zero.
  • A similar response reiterates the equation for time as \( t = \sqrt{2gh} \) and mentions that the final velocity can also be calculated using \( v = \sqrt{2gh} \).
  • One participant acknowledges a mistake in their previous statement.
  • Another participant expresses gratitude for the responses received.

Areas of Agreement / Disagreement

There is no explicit consensus on the discussion, as participants provide similar equations but do not engage in a deeper debate or challenge each other's claims. The discussion remains exploratory without clear resolution.

Contextual Notes

Participants assume ideal conditions, such as no friction and a uniform gravitational field, without addressing potential limitations or variations in real-world scenarios.

jamesd2008
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Hi,

If you no the height of an object only, assuming no frictional forces, and that it is on earh. Can you determine how long it will take to hit the ground?

Thanks
James
 
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Also the final velocity is also unknown and the initial velocity is zero?
 
I am assuming that you're talking about the height between the object and the floor. The answer is yes, and that is obvious from the equations that describe free fall, meaning the fall that is induced and preserved only by the force of gravitational attraction that the Earth exerts on the body.

So we have
[itex]h = \frac{1}{2} g t^2 \Leftrightarrow t = \sqrt{\frac{2h}{g}}[/itex]
and since you know h, you can calculate the required time. Using that t you can solve for the final velocity of the body, the one it has right before it reaches ground. And yes, since you let the body go at one point without pushing it downwards, the initial velocity is zero.
 
Last edited:
karkas said:
I am assuming that you're talking about the height between the object and the floor. The answer is yes, and that is obvious from the equations that describe free fall, meaning the fall that is induced and preserved only by the force of gravitational attraction that the Earth exerts on the body.

So we have
[itex]h = \frac{1}{2} g t^2 \Leftrightarrow t = \sqrt{2gh}[/itex]
and since you know h, you can calculate the required time. Using that t you can solve for the final velocity of the body, the one it has right before it reaches ground. And yes, since you let the body go at one point without pushing it downwards, the initial velocity is zero.

No t=square root (2h/g)
velocity = square root (2gh)
 
Yes sorry my bad.
 
Thanks for the reply's guys, much help :smile:
 

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