How long does it take for wave to travel the lenght of the string

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Homework Help Overview

The problem context involves determining the time it takes for a wave to travel the length of a string, given its fundamental frequency of 256 Hz. The subject area pertains to wave mechanics and properties of vibrating strings.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between frequency, wavelength, and wave speed. Some express uncertainty about how to approach the problem without the length of the string, while others attempt to calculate time based on frequency.

Discussion Status

Several participants have engaged in calculations related to the frequency and its implications for wave travel time. There is an indication of progress, with some participants expressing increased understanding of the concepts involved.

Contextual Notes

There is a noted absence of information regarding the length of the string, which is critical for determining the wave speed and travel time. Participants are also reflecting on their understanding of frequency and its role in the problem.

RaPiD
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Homework Statement



Fundamental frequency of a string fixed at both ends is 256 Hz. How long does it take for a wave to travel the length of string?

Homework Equations



V = f (lambda)

Otherwise, not really sure.

The Attempt at a Solution



I didn't really know how to approach this problem because the length of the string wasn't given because I was thinking that if I had the distance I could find the velocity and then the time.
 
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256 hz = 256 cycles/s

that means it takes 1/256 s/cycle, or 0.00390625 s/cycle.

so it's 0.00390625s, i think
 


thanks for the reply, but I think I go it now. I think since its fundamental frequency its half of the wavelength. And I completely forgot what frequency actually is.
 


The answer is 1.953 x 10-3 seconds. Is that what you got?
 


Yeah dx I got .00195 s , your last reply from my last question helped me a little more to understand it. Thanks again.
 

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