How long to heat a given volume of air?

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SUMMARY

The discussion centers on calculating the time required for an 8kW air heater to raise the temperature of 9m³ of air by 25°C. Using the specific heat capacity (cp) of 1005 J kg-1 K-1 and the density (ρ) of 1.534 kg m-3, the total energy required (Q) is determined to be 346875.75 J, equivalent to 0.097 kWh. Consequently, the time needed for heating is calculated to be approximately 43 seconds. Additionally, the pressure change due to the temperature increase is addressed using the formula p2 = (p1 * T2) / T1.

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evoke1l1
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Homework Statement


I am working on a problem where I need to determine the time taken for an air heater with an 8kW output to heat a volume of air of 9m^3 by 25C. I am neglecting all losses at the moment. It almost seems too simple in my mind that I'm concerned I'm overlooking something.

Homework Equations


cp = 1005 J kg-1 K-1
ρ = 1.534 kg m-3
Q = cp * m * dT

The Attempt at a Solution



Q = 1005 * (1.534 * 9) * 25 = 346875.75 J = 0.35MJ

As 1kWh = 3.6MJ:

0.35 / 3.6 = 0.097kWh required for a dT of 25C to heat a 9m^3 volume of air.

The time required would therefore be 0.097 / 8 = 0.012 hours or approximately 43 seconds.

Am I along the right lines here?
 
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Yes, you got it right. It really is that easy when you understand what you are doing.

Just for grins and giggles, what is the pressure of that air assuming the temperature is 25 deg C?
 
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Thank you for confirming this.

I’m assuming the change in pressure over the 25C change?

This would be caluculated by p2 = (p1 * T2) / T1 I believe.
 

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