The discussion focuses on calculating the difference in divisions between two oscilloscopic traces represented by the equations V1 = 10cos(10^4t) and V2 = 5cos(10^4t + pi/3). The time base setting is 0.1 msec/div. The calculated period of the signals is 0.628 milliseconds, leading to a difference of approximately 1.05 divisions due to the phase shift of pi/3, which corresponds to 1/6 of the total period.
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eehelp150 said:Would the difference between 10cos and 5cos add a factor of 2 or 1/2 to the # of divisions?
You are making this difficult for yourself if you are attempting to answer this question without first sketching how the oscilloscope is displaying these two signals.eehelp150 said:Would the difference between 10cos and 5cos add a factor of 2 or 1/2 to the # of divisions?
a. Same frequencyCWatters said:No. The 10 and 5 give you the amplitude. For example at a peak, when cos(...) =1, one waveform has the value 10 and the other 5.
Hints:
a) Both waveforms have a common 104t term. What does that mean?
b) One also has another term pi/3. What does that represent?
B would shift the graph over to the right by pi/3?CWatters said:Correct.
Which of a and b shifts the trace left to right along the time axis relative to the other?
So how many divisions will these two traces differ?CWatters said:Correct.
Although I think V2 would be shifted left relative to V1.
1/3 of the period?gneill said:You have calculated the period of the signals (the time for one cycle). How much of one period does the phase angle represent? What is it in milliseconds?
Can you show how you determined the 1/3 value? Is pi/3 really 1/3 of a full circle?eehelp150 said:1/3 of the period?
0.209 ms?
Pi/3 is 1/6 of the total period, so would it be 0.105ms or 1.05 divisions?gneill said:Can you show how you determined the 1/3 value? Is pi/3 really 1/3 of a full circle?
That looks better!eehelp150 said:Pi/3 is 1/6 of the total period, so would it be 0.105ms or 1.05 divisions?