How many electrons are missing on the suspended oil drop?

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SUMMARY

The discussion focuses on calculating the number of missing electrons from a positively charged oil drop suspended in an electric field. The key formula used is q = Ne, where q represents the charge on the drop, N is the number of missing electrons, and e is the elementary charge (approximately 1.6 x 10-19 coulombs). Participants confirm that to find the number of missing electrons, one must divide the positive charge of the drop by the charge of a single electron.

PREREQUISITES
  • Understanding of electric charge and Coulomb's law
  • Familiarity with the concept of electric fields
  • Knowledge of the elementary charge (e = 1.6 x 10-19 coulombs)
  • Basic algebra for solving equations
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  • Research the concept of electric field intensity and its effects on charged particles
  • Study the relationship between charge, mass, and force in electrostatics
  • Explore advanced applications of the oil drop experiment in physics
  • Learn about the quantization of charge and its implications in atomic theory
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Students studying physics, particularly those focusing on electrostatics, as well as educators looking for practical examples of charge quantization.

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Homework Statement



A positive charge oil drop weights X N. An electric field intensity of YN/C suspends the drop. How many electrons is the drop missing?

X and Y are given though I don't need to give them because I am wondering what formula to use.,



The Attempt at a Solution



I have already found the charge on the drop as q. now how would I find the amount of missing electrons? I am solving for N I know.


Would I do this: q=Ne?

Thanks
 
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Yes. The number of "missing" electrons is just the (+) charge on the drop divided by the charge on one electron.
 

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