How Many Excess Electrons Cause a 4.57 * 10^-21 N Repulsive Force?

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Homework Help Overview

The problem involves calculating the number of excess electrons on two small spheres that are 20.0 cm apart, given a repulsive force of 4.57 * 10^-21 N between them. The subject area pertains to electrostatics and Coulomb's law.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss manipulating the force equation to isolate the charge and then determining the number of electrons based on that charge. There are attempts to clarify the correct value of the constant k and its implications for the calculations.

Discussion Status

Some participants provide guidance on rearranging the formula and calculating the charge, while others express uncertainty about the results and calculations. There are indications of multiple interpretations of the calculations, with some participants suggesting errors in the arithmetic.

Contextual Notes

Participants question the accuracy of constants used and the interpretation of results, indicating potential confusion in the calculations. There is also mention of an online program providing feedback on the submitted answer.

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Homework Statement


Two small spheres spaced 20.0 cm apart have equal charge.

How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57 * 10^-21 N?

Homework Equations


F = 1/4pi*e_o * k * (|Q1|*|Q2| / r^2)

1/4pi*e_o = 8.988 * 10^-9

The Attempt at a Solution



Since we know the force, we just have to find how many excess electrons and since they have the same charge, we can just take that value and square it.

4.57 * 10^21 = 8.988 * 10^-9 * ((x * 10^-9)^2 / (.20)^2)

I've tried different values of X but I can't seem to get it to equate to given Force, and I'm not sure if I'm doing it right anymore.
 
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If you manipulate the equation before putting the numbers in then it will be a lot easier.

[tex]q^2 =\frac{r^2F}{k}[/tex]

The square root will give you the charge on each sphere and then you will have to divide that by the charge on an electron to determine the number of electrons on the sphere.
 
q^2 = r^2*F / k

q = sqrt(r^2*F / k)

r = .20m
F = 4.57 * 10^-21
k = 8.85 * 10^-12

sqrt( ((.20)^2 * (4.57*10^-12)) / (8.85*10^-12) )

Doing the math I get q = .000005

You said to take this value and divide by the charge of an electron? I'm not sure what to do with this value after I obtain q, I know this should give you the charge of q right?
 
In the equation I gave you [tex]k=\frac{1}{4\pi \epsilon_0}[/tex] so the value you used is incorrect. As for q, that is the charge on 1 sphere and to find how many eectrons cause the charge you need to divide q by the charge on an electron.
 
Yes, you're right I must of have missed that.

From the new calculations:

sqrt( ((.20)^2 * (4.57*10^-12)) / (1/ 4*pi*(8.85*10^-12)) )

q = 1.42*10^-16

Charge of Electron = 1.602 × 10^-19

So you said take q / charge of electron?

(1.42*10^-16) / (1.602* 10^-19) = 8.9*10^-36?

I entered that in as the solution, but the online program says it's still incorrect.
 
Last edited:
Should come out at about 890.
 
Kurdt said:
Should come out at about 890.

Yea that's the answer, I guess I mis-interpreted the answer. Thanks!
 
Just looks like you made a minor error on the calculator when you were plugging the numbers in. If you try again you'll probably get the correct answer.
 

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