Calculating H3O ions in a drop of water at 25 °C

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SUMMARY

The calculation of H3O ions in a drop of pure water (0.050 mL) at 25 °C reveals a discrepancy between the user's answer and the textbook's. The user initially calculated 5 x 10^-12 H3O ions based on a concentration of 1.0 x 10^-7 moles per liter. However, the correct approach involves multiplying the moles by Avogadro's number (6.022 x 10^23), resulting in the textbook's value of 3 x 10^12 H3O ions.

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Hello!
Here is a problem that looked easy for me, but my answer differs from the textbook's one. Please, help me to see my mistake.

How many H3O ions are present in one

drop (0.050 mL) of pure water at 25 °C?

Here is how I solved it:
There are 1.0 x 10^-7 in one liter.
We have 0.000050 liters, hence 0.00005 x 1.0 x 10^-7 = 5 x 10^-12

The book gives 3 x 10^12

Thank you!
 
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You do understand the difference between number of moles and number of ions?
 
Borek said:
You do understand the difference between number of moles and number of ions?
Oh! What a shame ) Sorry. Yes. I have to multiply my moles 5 x 10^-12 by 6.022 x 10^23
Thank you!
 

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