How many ion-pairs are there in normal conditions in the air?

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SUMMARY

The discussion centers on estimating the number of ion-pairs in normal atmospheric conditions, specifically at 1 atm and 300K. Participants estimate approximately 1,800 ions per cubic centimeter based on cosmic radiation, with variations due to factors like humidity, radioactivity, and environmental conditions. The conversation highlights the complexity of measuring ion-pair production, suggesting that experimental measurement is the most reliable method for obtaining accurate figures. The influence of environmental variables, such as dust and electrical systems, is also emphasized.

PREREQUISITES
  • Understanding of ionization processes in atmospheric physics
  • Familiarity with cosmic radiation effects on air composition
  • Knowledge of measurement techniques in laboratory settings
  • Basic principles of radioactivity and its environmental impact
NEXT STEPS
  • Research methods for measuring ion-pair production in controlled environments
  • Explore the effects of humidity on ionization levels in the atmosphere
  • Study the influence of different materials (e.g., concrete, dust) on ion production
  • Investigate the role of cosmic radiation in atmospheric chemistry
USEFUL FOR

Researchers in atmospheric science, physicists studying ionization, laboratory technicians measuring environmental radiation, and anyone interested in the effects of cosmic radiation on air quality.

ORF
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Hello,

I don't know how to compute that number, but probably is a kind of reference value...

Q: How many ion-pairs are there in normal conditions* in the air?

(This is not homework, it is just out of curiosity.)

Thank you for your time.

Regards,
ORF
* 1 atm, 300K.
 
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You've forgotten to mention humidity, e.g. Lenard effect in rain, snow, wind, clouds, height, ##O_3##, daytime, location on earth, radioactivity, and condensation germs, esp. dust, plus a few extraterrestrial effects. Would take a while to find figures of exactly your conditions, but is basically possible. It seems that this is a whole branch in meteorology.

So the question is: What do you want to hear? Approximately 5 new pairs per second and cubic centimeter due to cosmic radiation? Under consideration of the recombination mechanism, this results in circa 1,800 ions per cubic centimeter.
(Found in a book "Encyclopedia of Medical Radiology".)
 
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Hello,

I would be interested in a rough estimation, the order of magnitude, rather than an exact reference number.

The conditions would be:
  • humidity: 90%
  • no rain/snow/no clouds,
  • no wind (inside lab),
  • at sea level,
  • north hemisphere,
  • normal background ~100 nSv/h
  • little of dust

Well, you mention radioactivity: I would like to know if a home-made electroscope can be discharged by a low specific-activity source ( granite, KCl ).

Thank you for your time.

Regards,
ORF
 
I think the only way to find out is to measure it. If this figure in the book ##1,800 \,\,ions / cm^-3## is correct for the usual atmosphere, then it shouldn't be too different in a lab, where there might be less natural sources, but maybe more artificial. AFAIK has e.g. concrete a higher radioactivity than normal. So whether 2,000 ions are sufficient to create a discharge effect is hard to tell without measurements. I've come across the following experiment:
upload_2018-4-14_19-16-20.png

of average charges in a room (per day).
However, electrical heating and cooling systems have a strong effect of several magnitudes difference. So my conclusion from reading a bit about the topic is, that there are far too many unknown variables to give a qualified answer. I think measurement is the only valid answer here.
 

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Hello,

if the order of magnitude is 1e3 ions/cm3, it is fine: I expect a production of 1e6 ions/cm3/s (upper limit) from a weak source.

Regards,
ORF
 
ORF said:
Hello,

if the order of magnitude is 1e3 ions/cm3, it is fine: I expect a production of 1e6 ions/cm3/s (upper limit) from a weak source.

Regards,
ORF
For an electrical heater I've read something about 500,000 /cm^3, which is close to your estimation. Smoke and particulates are other sources. That's why I said that it depends on really many variables. I even found old physical papers (1903, not English) where they investigated the influence on electrical experiments.
 

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