How Many Molecules in 1 mL of a Vacuum at 27.0 degrees Celsius?

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Discussion Overview

The discussion revolves around calculating the number of molecules in 1 mL of a vacuum at a temperature of 27.0 degrees Celsius, using the ideal gas law. Participants explore the implications of significant figures and unit conversions in their calculations.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a calculation using the ideal gas law, expressing uncertainty about the appropriate number of significant figures to use in their final answer.
  • Another participant confirms that a liter is equivalent to 1000 mL, prompting a discussion about whether to multiply or divide the calculated number of molecules to convert from liters to milliliters.
  • There is a clarification that the volume of 1 mL should be treated as having significant figures, with suggestions on how to interpret this in the context of the problem.
  • A later reply asserts that the initial calculation was correct and emphasizes the importance of interpreting the volume as exactly 1 mL, allowing for flexibility in significant figures.

Areas of Agreement / Disagreement

Participants express differing views on how to handle significant figures and unit conversions, indicating that there is no consensus on these aspects of the problem.

Contextual Notes

Participants discuss the implications of significant figures based on the wording of the question and the calculations performed, but there are no definitive resolutions to these considerations.

maceng7
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Homework Statement



A vacuum pump on Earth can produce a vacuum with a pressure as low as 1.00*10^-8 torr. How many molecules are present in each mL at a temperature of 27.0 degrees Celsius?

V = 1mL = 10^-3 L <-- How many sig figs should I use here? Should I make it 1.00*10^-3L or keep it 10^-3L?
P = 1.315789 atm
T = 300.15 K
n = ?

Homework Equations



Pv = nRT

The Attempt at a Solution



PV =nRT

n = PV / RT

= (1.315789atm)(1.00*10^-3L) / (0.08206 Latm / Kmol)(300.15K)

= 5.342156*10^-16mol * 6.022*10^23 molecules

= 3.22*10^8 molecules / L <--- How do I change my answer back to how many molecules/mL and how many sig figs should my answer reflect? 1 or 3?
 
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Yeah so would I just multiply my answer by 1000?
 
okay so think a liter is 1000 times bigger than a mL right? so that means it can hold 1000
times the # of molecules that an mL would have? so do you multiply or divide?
 
my mistake, yeah I'd definitely divide my answer by 1000. Also for sig figs, since the question says "one milliliter" how many digits should I interpret that as? Should I let the volume = 1mL, which would give me one sig fig in my answer or should I just make it 1.00mL and include 3 sig figs in my answer?
 
Your answer was already correct - you used 10-3L as a volume, so you calculated number of moles in 1 mL. You added L at the very end of the calculation out of nothing, confusing yourself.

Question says "in each mL" which probably means "exactly mL" - so there is as many significant digits as you want. Sure, it doesn't make sense to report all digits your calculator displays - I would go with three.
 

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