Calculating Moles Using the Ideal Gas Law

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Discussion Overview

The discussion revolves around the calculation of moles of gas using the Ideal Gas Law, specifically addressing a homework problem involving the conversion of pressure units and the application of the equation PV=nRT. The scope includes mathematical reasoning and technical explanation related to gas laws.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents a calculation using the Ideal Gas Law and arrives at an initial answer of 114 moles, later correcting it to 0.114 moles.
  • Another participant questions the units used for the gas constant R and emphasizes that the pressure unit must match the units of R.
  • Participants discuss the implications of using different units for pressure, noting that R can take various forms depending on the units employed.
  • There is a hint provided regarding the relationship between J/(K*mol) and pressure in kPa, suggesting a need for clarity on unit conversions.

Areas of Agreement / Disagreement

Participants generally agree that the units must be consistent when using the Ideal Gas Law, but there is no consensus on the specific units that should be used for pressure.

Contextual Notes

Limitations include potential confusion over unit conversions and the specific values of R that may apply in different contexts. The discussion does not resolve how to handle these unit discrepancies definitively.

Who May Find This Useful

Students working on gas law problems, educators teaching Ideal Gas Law applications, and anyone interested in the nuances of unit conversions in physical chemistry.

kasse
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Homework Statement



When the volume of a gas is 2.81 L, the pressure is 740 Torr and the temperature is 20oC, how many moles of gas is there?

Homework Equations



PV=nRT

The Attempt at a Solution



740 Torr = 740*133.3 = 98.6*10^3 Pa
Temperature in Kelvin: 293 K

n = PV/RT = (98.6*10^3 * 2.81) / (8.3145*293) = 114 moles

The corret answer is 0.114 moles. Does this mean that when using the ideal gas law, the pressure should be in kPa?
 
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What are your units for R? The pressure unit must match that.
 
J/(K*mol)
 
Does this mean that when using the ideal gas law, the pressure should be in kPa?

All it means is that units of data must match units of R.

R can take any value, it all depends on the units used. For example - 10.7316 ft3·psi·°R-1·lb-mol-1. Don't ask me what lb-mol is :smile:

Check how J/(K*mol) relates to pressure in kPa. What is Pa?
 
kasse said:
J/(K*mol)

Hint: "Oh, I thought it was in L kPa/mol K!"
 

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