How many nodes of each degree are there in this graph?

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In the discussion about the number of nodes of each degree in a graph, it is established that there must be an even number of vertices with odd degrees, supported by the handshake theorem. The proposed configuration of 4 vertices of degree 5 and 2 vertices of degree 2 is examined for correctness. Participants agree that this configuration meets the requirements, but emphasize the need to form and solve the equation to confirm. The method involves denoting the number of nodes with degree 2 as x and those with degree 5 as 6 - x, leading to a simple linear equation. Ultimately, solving this equation will validate the proposed node distribution.
r0bHadz
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Homework Statement
A graph has 12 edges and 6 nodes, each of which has degree of 2 or 5. How many nodes
are there of each degree?
Relevant Equations
handshake theorem.
2m = summation of degree of each vertice where m = # of edges
there must be an even number of vertices of odd degree, and from the handshake theorem, 2m = 2(12) = 24

the only way we can get this from 6 vertices using 2 and 5 is:

4 vertices of degree 5, 2 vertices of degree 2

does this seem correct??
 
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If we denote with ##x## the number of nodes with degree ##2## and with ##6 - x## the number of nodes with degree ##5## then according to the theorem you say, you have a simple equation of the first degree in ##x##.
Its solution gives what is asked.
 
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QuantumQuest said:
If we denote with ##x## the number of nodes with degree ##2## and with ##6 - x## the number of nodes with degree ##5## then according to the theorem you say, you have a simple equation of the first degree in ##x##.
Its solution gives what is asked.
So do I just plug and chug to find out? It seems like 4 of degree 5 and 2 of degree 2 meets the requirements?
 
r0bHadz said:
So do I just plug and chug to find out? It seems like 4 of degree 5 and 2 of degree 2 meets the requirements?

I would say yes, it seems so, but you must first form the equation and then solve it, in order to see it.
 

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