How Many Orbits Does an Electron Make in the Bohr Model?

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SUMMARY

The discussion centers on calculating the number of orbits an electron makes around a proton in the Bohr model of the hydrogen atom. The angular speed of the electron is determined to be 4.12 × 1016 rad/s. To find the number of orbits per second, the correct approach involves dividing the angular speed by 2π, which represents the conversion from radians to revolutions. Despite this, users encountered discrepancies when verifying their results on an educational platform.

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  • Understanding of the Bohr model of the hydrogen atom
  • Familiarity with angular velocity and linear velocity concepts
  • Knowledge of unit conversion between radians and revolutions
  • Basic algebra for manipulating equations
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MozAngeles
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Homework Statement


The Bohr Atom The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proton. In the lowest-energy orbit the distance from the proton to the electron is 5.29 * 10^- 11 m, and the linear speed of the electron is 2.18 *10^6 m/s.
A. What is the angular speed of the electron? got it.. \omega =4.12×10^ 16 rad/s

B. How many orbits about the proton does it make each second? ??

Homework Equations


omega=linear velocity/radius
1rev=2\pi rad


The Attempt at a Solution


you would think you would just divide the result from question A (4.12*10^16 rad per s) by the conversion factor of rev to rad (2\pi). However, this is showing up to be wrong on the website.. I have no idea of what else i can do...
 
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Hi MozAngeles! :smile:

(have a pi: π and an omega: ω and try using the X2 tag just above the Reply box :wink:)
MozAngeles said:
you would think you would just divide the result from question A (4.12*10^16 rad per s) by the conversion factor of rev to rad (2\pi). However, this is showing up to be wrong on the website.. I have no idea of what else i can do...

Looks ok to me. :confused:
 

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