Right if you used the right v and r and the math is right.nmsurobert said:Homework Statement
Calculate the centripetal acceleration of an electron in the lowest Bohr orbit.
Homework Equations
no equations were given but i think i have to use ac = v2/r
were v = 2.19 x 106 m/s (speed of electron in its lowest orbit)
r = ao = 5.29 x 10-11m (minimum radius)
The Attempt at a Solution
so
(2.19 x 106m/s)2/(5.29 x 10-11m)
= 9.07x1022 m/s2
does this look correct?
Yer' welcome! That moniker was given to me at work, my 1st name being rudy. I fear there was some rationale behind it ... :-)nmsurobert said:thank you rude man! youre not as rude as your name suggests ;-)
Electron acceleration in its lowest orbit is a result of the electromagnetic force between the negatively charged electron and the positively charged nucleus. As the electron travels in a circular orbit around the nucleus, it experiences a constant force towards the center, causing it to accelerate.
Electron acceleration in its lowest orbit is important because it determines the stability and energy levels of atoms. The acceleration of electrons in their lowest orbit determines the characteristic spectrum of an element and is the basis of chemical bonding.
Yes, the speed of an electron in its lowest orbit can be calculated using the formula v = √(Zke²/mr), where Z is the atomic number, k is the Coulomb constant, e is the charge of an electron, m is the mass of the electron, and r is the radius of the orbit.
The acceleration of an electron in its lowest orbit does not affect its energy. In a circular orbit, the kinetic energy of the electron remains constant, while its potential energy decreases as it moves closer to the nucleus. This results in a stable orbit for the electron.
If an electron in its lowest orbit gains energy, it can move to a higher energy level, resulting in an excited state. Conversely, if it loses energy, it can move to a lower energy level, releasing energy in the form of light. This is the basis of atomic emission and absorption spectra.