How Many Parts Must a 100Ω Wire Be Cut Into to Achieve 1Ω Total Resistance?

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SUMMARY

The problem involves determining how many equal parts a 100Ω resistance wire must be cut into to achieve a total resistance of 1Ω when connected in parallel. The solution requires applying the formula for total resistance in parallel circuits, which is given by 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn. For n equal resistances, this simplifies to R_total = R/n, leading to the conclusion that the wire must be cut into 100 parts.

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Karolis
I really need you help to solve this problem. I've been trying to solve it for like an hour but still can't do it. So here it is.
100[tex]\Omega[/tex] resistance wire is cut in equal parts, which are connected in parallel. They're total resistance is 1[tex]\Omega[/tex]. In how many parts the wire is cut?

Thank you.
 
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Karolis said:
I really need you help to solve this problem. I've been trying to solve it for like an hour but still can't do it.



So here it is.
100[tex]\Omega[/tex] resistance wire is cut in equal parts, which are connected in parallel. They're total resistance is 1[tex]\Omega[/tex]. In how many parts the wire is cut?
Welcome to Physics Forums.

You seem you have forgotten to use the homework template, particularly sections two and three which ask you to write down the relevant equations and detail an attempted solution.
 

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