How Many Photons Do a Light Bulb and Microwave Emit Per Second?

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SUMMARY

The discussion focuses on calculating the number of photons emitted per second by a 75 Watt light bulb and an 850 Watt microwave, with wavelengths of 500 nm and 150 mm, respectively. Participants emphasize using the equation E = hν or E = c/λ to determine the energy per photon. The consensus is that quantum effects are not significant for these devices, as the quantized nature of radiation does not play a crucial role in their operation. The microwave's wavelength was corrected from 150 nm to 150 mm, clarifying the context of the discussion.

PREREQUISITES
  • Understanding of Planck's equation E = hν
  • Familiarity with the speed of light equation E = c/λ
  • Basic knowledge of power and energy relationships in physics
  • Concept of photon emission and quantization in electromagnetic radiation
NEXT STEPS
  • Research the implications of quantum effects in everyday appliances like microwaves and light bulbs
  • Learn about the relationship between power output and photon emission rates
  • Explore the differences between blackbody radiation and non-blackbody sources
  • Investigate the significance of wavelength in determining photon energy
USEFUL FOR

Students in physics, educators teaching quantum mechanics, and professionals in electrical engineering or appliance design will benefit from this discussion.

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Homework Statement


Consider a 75 Watt light bulb and an 850 Watt microwave. If the wavelengths of the radiation they emit are 500nm and 150nm, respectively, estimate the number of photons they emit per second. Are the quantum effects important in them?

Homework Equations


?

[tex]M(T) = \sigma T^4[/tex] Now this gives me the watts per meter^2. But I don't know the meter^2. (This doesn't make sense to me because the watts/meter^2 should be a function of the distance, farther out --> less watts/meter^2, but this function says nothing of distance...)

The Attempt at a Solution


Dont know where to start!

edit- My thoughts are I need to get the Joules per second emitted from the object. I can then turn this into photons per second using the relationship [tex]E = h\nu[/tex]

Thx for any help!
 
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Your second thoughts are correct, you don't need to consider the blackbody (which the microwave isn't). Just use E=hv , or E = c/lambda to get the energy per photon then the power you have been given.
ps I think you have misread the wavelength for the microwave it should probably be a few cm, 150nm is UV.
 
Yes you are right, the microwave is 150 mm.

Now I have the answers in photons/second. The question "Are the quantum effects important in them?". I have to figure out if the quantized nature of the radiation is significant. hmm... I am thinking its no, but I have no reason for that. I don't see and quantized values in the equations I wrote...
 
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