How Much Additional Mass Can a Floating Air Mattress Support?

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SUMMARY

The discussion focuses on calculating the additional mass that a floating air mattress can support, given its dimensions and densities of water and air. The air mattress measures 2.0m in length, 0.50m in width, and 0.08m in thickness, with a mass of 2.0kg. The correct calculation for the additional mass, m, is determined to be 79.9kg, while the initial calculation yielded 78.1kg. The discrepancy arises from the incorrect handling of the density of air in the equation used to solve for m.

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mizzy
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Homework Statement



A rectangular waterproof air mattress is 2.0m long, 0.50mwide and 0.08m thick. It has a mass of 2.0kg and is supporting an additional mass of m, while floating in the water,
calculate the mass, m, assuming the density of water is 1000kg/m^3 and density of air is 1.29kg/m^3

Homework Equations



B = weight of displaced fluid

B= density of water x volume * g

where B = mass of 2kg, unknown mass and mass of air

The Attempt at a Solution



I solved it and i got 78.1kg. The answer is 79.9kg

this is what i did:

m1g + m2g + density(air) * V *g = density(water) * V * g

solve for m2:

m2 = density(water) * V - density(air) * V - m1
m2 = 1000(0.08) - 1.29(0.08) - 2
m2 = 78.1kg

Can someone point out where i went wrong?
 
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No idea how to get answer that you listed as correct, IMHO it is off by 2 kg, but

mizzy said:
m2 = 1000(0.08) - 1.29(0.08) - 2
m2 = 78.1kg

this is just incorrect. Perhaps you have rounded down intermediate results, or just keyed those numbers wrong in your calculator.

800 - 0.1032 - 2 = 77.8968 ≈ 77.9
 

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