How Much Charge Remains on a Capacitor After 4 Milliseconds in a Circuit?

[Wizardofwaz]

Homework Statement

A capacitor is charged to 1 coulomb; the capacitance is 6.00×10-5 farads. Then a switch is closed which puts the capacitor in a closed circuit with a resistor; the resistance is 9.20×10^1 ohms. Calculate the charge on the capacitor after 4.00 milliseconds. (1 ms = 0.001 s)

Homework Equations

I=V/R
C=Q/V

The Attempt at a Solution

Final charge=1 Coulomb * 1.602E-19-.004/(92*6E-5)

1.602E(2.71828)^.004/(92*6E-5

 

[inhere]

You are simply using Q = Qo*e^(-t/tau). And tau = R*C, t = 4E-3 s. Take another look at RC circuits and the charging and discharging capacitor relations.

 

[Wizardofwaz]

what is e