You seem to be having some difficulty distinguishing the units of various electrical quantities. The above formula yields C, the Capacitance of the capacitor, not the energy. Energy has the units Joules.ME_student said:Energy stored on a capacitor is given by C=(epsilon*A)/(d)
Epsilon is a constat
A is the area of the plate
d is the distance between the plates
And that's an expression for the current (I in amps) , or rate of change of change charge (Coulombs) on the capacitor.the equation with voltage is Q=C*dv/dt
If you integrate current over time what do you get? Remember that current is the rate of flow of charge, or dQ/dt. That means the area under the curve represents...?ME_student said:I am currently working on the problem. I am trying to understand what the tangent to the graph or the total area underneath a graph represents when you have a graph that may have voltage respect to resistance, power respect to resistance, current respect to time, etc.
Okay, that method is correct, but your value for charge Q is not correct and the units will not be current (mA) but Coulombs (C). Can you show more detail for your integration steps?ME_student said:I said Q=integral of 50e^-2000t with limits of integration of 0 to 500microsec. I get 0.015803mA then I used C=Q/v to get volate. After that I use w=1/2(CV^2)
But I don't get the correct answer.
The energy stored in a capacitor can be calculated using the equation E = 1/2 * C * V^2, where E is the energy in joules, C is the capacitance in farads, and V is the voltage across the capacitor.
Energy stored in joules is a larger unit of measurement compared to energy stored in microjoules. 1 microjoule is equal to 0.000001 joules. Microjoules are typically used to measure small amounts of energy, such as in capacitors.
To convert energy stored in joules to microjoules, you can multiply the number of joules by 1,000,000. For example, 0.00005 joules would be equivalent to 50 microjoules.
The energy stored in a capacitor in microjoules is important because it determines the capacitor's ability to store and release electrical energy. Knowing the energy stored can also help in designing and choosing the right capacitor for a specific application.
The energy stored in a capacitor can be measured using a multimeter or a dedicated capacitor tester. These devices can measure the voltage and capacitance of the capacitor, which can then be used to calculate the energy stored using the equation E = 1/2 * C * V^2.