Network -- Current passing through a capacitor

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SUMMARY

The discussion focuses on calculating the charge acquired by a capacitor when a current i(t) is passed through it over a specified time interval. The current is defined with a slope of 2.5 microamperes per microsecond for the first 3 microseconds, resulting in a charge of 7.5 microcoulombs. Participants emphasize the importance of using the integral of current to determine charge accumulation, akin to using velocity-time graphs for displacement. The key equation relating voltage to the integral of current is also highlighted as essential for solving the problem.

PREREQUISITES
  • Understanding of capacitor charging principles
  • Familiarity with current-time graphs
  • Knowledge of calculus, specifically integration
  • Basic concepts of electrical circuits
NEXT STEPS
  • Study the relationship between current and charge in capacitors
  • Learn how to apply integration to find charge from current functions
  • Explore the equation relating capacitor voltage to current over time
  • Review examples of current-time graphs and their areas
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Students studying electrical engineering, physics enthusiasts, and anyone looking to deepen their understanding of capacitor behavior in circuits.

anand raj
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Homework Statement



A current i(t) as shown in the figure is passed through a capacitor. the charge (in micro coulomb) acquired by the capacitor after 5 micro seconds
rter_zpsebcc1b3b.jpg


Homework Equations



here slope is given for 3 microsecond ie. current=dq/dt = 2.5 charge upto here = 3*2.5=7.5 micro seconds do not know what to do/unable to interpret

The Attempt at a Solution

 
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Your class notes (or google) have an equation relating the capacitor voltage to the integral of its current. What is this equation?
 
The amount of charge accumulated between time ta and time tb is the area under the current-time graph between those times. It's like when you used v-t graphs to find displacement.
 

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