How much energy is dissipated in the first bounce?

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SUMMARY

The discussion focuses on calculating the energy dissipated during the first bounce of a basketball dropped from a height of 1.4 meters. The initial potential energy (U) is calculated using the formula U=mgy, resulting in 9.604 J. After the first bounce, the basketball rises to 66% of its original height, which is 0.924 meters, leading to a potential energy of 6.304 J. The energy dissipated in the first bounce is determined to be 3.3 J by subtracting the potential energy after the bounce from the initial potential energy.

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  • Understanding of gravitational potential energy (U=mgy)
  • Basic knowledge of energy conservation principles
  • Familiarity with kinetic energy concepts
  • Ability to perform calculations involving percentages and height
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emily081715
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Homework Statement


A 0.70-kg basketball dropped on a hardwood floor rises back up to 66 % of its original height. If the basketball is dropped from a height of 1.4 m , how much energy is dissipated in the first bounce?

Homework Equations


U=mgy

The Attempt at a Solution


U=(0.70)(9.8)(1.4)
=9.604 J
i'm not sure where the error is
 
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That's the potential energy that the basketball started with. How much total energy did the basketball start with?

Now, can you tell how much energy the basketball had after the first bounce?
 
olivermsun said:
That's the potential energy that the basketball started with. How much total energy did the basketball start with?

Now, can you tell how much energy the basketball had after the first bounce?
how do i find how much energy it starts with, i thought that would be the potential energy? would i need to find energy by adding potential and kinetic, cause if so, i don't have a speed
 
Typically in these problems if they say the ball was "dropped" they mean it was just released with 0 initial speed.

So what about the info you are given regarding the energy after the first bounce?
 
olivermsun said:
Typically in these problems if they say the ball was "dropped" they mean it was just released with 0 initial speed.

So what about the info you are given regarding the energy after the first bounce?
wouldn't i still need the final energy to calculate the kinetic energy of the first bounce? after the bounce is 66% of the original height so 0.924m
 
You have the max height after the first bounce, so that tells you the potential energy. What is the kinetic energy at the very moment that the max height is achieved?
 
olivermsun said:
You have the max height after the first bounce, so that tells you the potential energy. What is the kinetic energy at the very moment that the max height is achieved?
0?
 
Sure, so you have all the information you need.
 
olivermsun said:
Sure, so you have all the information you need.
how?
 
  • #10
emily081715 said:
how?
do i just subtract potential energies from the start and the max of second bounce
 
  • #11
This part I leave to you to consider. :wink:
 
  • #12
emily081715 said:
do i just subtract potential energies from the start and the max of second bounce
the answer is 3.3 thanks for walking me through
 

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