How Much Force Did the Second Person Apply to the Soccer Ball?

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Two people kick a soccer ball at the same time. One person with a force of 100 N [N 25 degrees W]. The result is the ball moving 200m/s^2 [S 15 degrees W]. With what force did the second person kick the ball.

I'm not sure how to do this question, any help is appreciated greatly.

Thanks in Advance.
 
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Hey there SteveyBee :smile: I would start by drawing a force diagram on the soccer ball. You know the magnitude and direction of one force. You don't know the magnitude and direction of the other force, so just draw it wherever you think it should go (doesn't really matter where). You know that the vector sum of these two forces will give the total force Ftot. By Newton's second law, you should be able to relate Ftot to the acceleration of the ball.
 
Thanks for the replies.

I understand the first free body diagram, but I don't have a clue about what to find first.
Also is there an applied force on the ball while it is in the air?
 
you must take the two vectors given, your first kicker vector and your resultant vector, break that down into your x,y components using Sin and Cos. Then subtract the kickers vector from the resultant vector then you will be left with 2 dimensions for a right triangle, then use pythagoreon theorem to solve for the missing side, and then sin cos and tan functions to find the angle