How Much Force Exerts on a Bullet in a Rifle Barrel?

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SUMMARY

The discussion centers on calculating the force exerted on a 4.5 g bullet traveling at a speed of 318 m/s within a 0.75 m long rifle barrel. Using the formula for force, which is derived from Newton's second law (F = ma), the force can be determined by first calculating the acceleration of the bullet. The force exerted on the bullet while it travels down the barrel is approximately 57.3 Newtons, assuming constant acceleration.

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A 4.5 g bullet leaves the muzzle of a rifle with a speed of 318 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.75 m long barrel of the rifle? The answer is in Newtons.

Thanks for any input :)
 
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What do you know about the bullet after a constant has force as acted upon it over a given distance? (force times distance = ?)
 

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