How Much Force Stopped the Diver Underwater?

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SUMMARY

The discussion centers on calculating the force required to stop a 50 kg diver who enters the water at 4 m/s and comes to a stop 3 meters underwater. The correct approach involves using the kinematic equation v² - u² = 2ad to determine the acceleration, where v is the final velocity (0 m/s), u is the initial velocity (4 m/s), and d is the distance (3 m). After finding the acceleration, the net force can be calculated using F = ma, where 'm' is the diver's mass and 'a' is the calculated acceleration.

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Homework Statement


A 50 kg diver enters the water moving at 4 m/s. He eventually comes to a stop 3 meters below the water surface. What amount force brought the diver to a stop?

Homework Equations


Is the acceleration -9.8 m/s^2?
Then, would you use F = ma to find the net force?

The Attempt at a Solution


i tried to do F = (50 kg)(-9.8 m/s^2) but i don't think that's right...

Thank you.
 
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plqaokws said:

Homework Statement


A 50 kg diver enters the water moving at 4 m/s. He eventually comes to a stop 3 meters below the water surface. What amount force brought the diver to a stop?


Homework Equations


Is the acceleration -9.8 m/s^2?
Then, would you use F = ma to find the net force?


The Attempt at a Solution


i tried to do F = (50 kg)(-9.8 m/s^2) but i don't think that's right...

Thank you.

This will not work as the acc is not equal to -g. You have the velocity when the body touches the water surface. This is the initial velocity. Now the final velocity is zero.And the distance is 3m. So by v^2-u^2=2ad.You can find a, and then you can apply f=ma.Here v is the final velocity and u is the initial velocity.
 

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