How Much Force to Overcome Static Friction and Move a Crate?

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SUMMARY

The minimum force required to overcome static friction and initiate movement of an 875 N crate is determined using the static friction coefficient of 0.56. The formula to calculate the force is Fp = \mus * N, where N is the normal force equal to the weight of the crate. Therefore, the minimum force Fp needed to start sliding the crate is 490 N (0.56 * 875 N). Once the crate is in motion, the kinetic friction coefficient of 0.47 applies, requiring a reduced force to maintain movement.

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  • Understanding of static and kinetic friction coefficients
  • Knowledge of Newton's laws of motion
  • Ability to calculate normal force in physics
  • Familiarity with basic algebra for solving equations
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  • Study the derivation of the static friction formula Fp = \mus * N
  • Learn about the differences between static and kinetic friction
  • Explore applications of Newton's laws in real-world scenarios
  • Investigate the effects of surface materials on friction coefficients
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to explain concepts of friction and motion.

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Homework Statement



The weight of the crate is 875 N. You push it with a force of magnitude 300 N but it doesn't move

What is the magnitude Fp of the minimum force you need to exert on the crate to make it start sliding along the floor? Let the coefficient of the static friction [tex]\mu[/tex]s coefficient the crate and the floor be 0.56 and that of kinetic friction, [tex]\mu[/tex]k, be 0.47



Homework Equations







The Attempt at a Solution



I tried solving it by using the formula fk = [tex]\mu[/tex]kn but it told me that I'm going about the problem wrong. It says that I need to study the condition for which the crate ceases to be at rest, that is, the condition for which static friction ceases to be valid. I used kinetic friction though, so I don't know what to do now.
 
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Use the static coefficient of friction in your formula.
Once it has started moving, the lower dynamic coefficient comes into play and a smaller force will suffice to keep it moving.
 

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