How much force will be required to remove the lid?

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SUMMARY

The discussion focuses on calculating the force required to remove a massless lid from an airtight box when subjected to different atmospheric pressures. Initially, at a mountain altitude with atmospheric pressure of 81,000 Pa, the force calculated is 3,240 N. When the box is taken to sea level, where the atmospheric pressure is 101,200 Pa, the force increases to 4,052 N. The key equation used is F = PA, emphasizing the importance of pressure difference in determining the force needed to open the lid.

PREREQUISITES
  • Understanding of pressure concepts, specifically atmospheric pressure.
  • Familiarity with the equation F = PA for calculating force.
  • Basic knowledge of units of measurement, particularly Pascals (Pa).
  • Concept of pressure difference and its effect on force.
NEXT STEPS
  • Research the implications of pressure differences in fluid mechanics.
  • Learn about the effects of altitude on atmospheric pressure.
  • Explore applications of the equation F = PA in real-world scenarios.
  • Investigate how to calculate force in systems with varying pressures.
USEFUL FOR

This discussion is beneficial for physics students, engineers, and anyone interested in understanding the principles of pressure and force in closed systems.

iseidthat
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Homework Statement


An airtight box has a removable (massless) lid of area 4·10-2 m2. A lid is placed on it while it is on top of a mountain (where Patm=0.81·105 Pa). It is then taken to sea level, where Patm = 1.013·105 Pa. How much force will be required to remove the lid?

Homework Equations


F=PA

The Attempt at a Solution


For the first part:
F=PA=.04 x 81000=3240 N
For the second part:
F=PA= .04 x 101200=4052 N

is there a change in pressure type of equation?
 
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You are only interested in the change of pressure. - this gives you the pressure differnce between the inside and outside of the box and so the force to open it
 

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