Net Force on airplance cabin surface

Click For Summary

Homework Help Overview

The discussion revolves around calculating the net force on an airplane cabin surface due to pressure differences at various altitudes. The problem involves understanding the pressures inside and outside the cabin, specifically at sea level and at cruising altitude, and how these pressures relate to the force exerted on the cabin structure.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between pressure and force, questioning how to apply the pressure difference to find the net force. Some express confusion about the use of sea-level pressure in calculations and the rationale behind using pressure as multiples of atmospheric pressure.

Discussion Status

Participants are actively engaging with the problem, with some offering guidance on breaking down the steps to understand the forces involved. There is a recognition of the importance of grasping the underlying physical concepts rather than merely memorizing formulas. Multiple interpretations of the problem are being explored, particularly regarding the calculation of forces based on pressure differences.

Contextual Notes

Some participants mention the constraints of time due to upcoming exams, which may influence their understanding and engagement with the material. There is also a discussion about the common practice of expressing pressures as multiples of standard atmospheric pressure.

tbstar
Messages
3
Reaction score
0

Homework Statement



5. The air pressure at sea level on a cold day is P0 = 1.013 x 105 Pa. At 10.0 km above sea level the air pressure is 0.30 P0 ; however a commercial jet plane keeps the pressure in the passenger and crew section at 0.75 P0 . If the surface area of the cabin structure is 1200 m2 , find the net force on the cabin surface due to the differential of pressure.

Homework Equations





The Attempt at a Solution



P net pressure = 0.75 - 0.30 = 0.45 Pa
F=?
 
Physics news on Phys.org
Welcome to PF!

Hi tbstar ! Welcome to PF! :smile:

Pressure is defined as force per area.

So force = … ? :smile:
 
I wanted to understand this solution:

F = P x A = 0.45 x 1.013x10e5 x 1200
F= 5.47 x 10e7

Why we are multiplying the difference pressure between the air and the cabin by the pressure at sea level?

Thanks for the warm welcoming
 
You can do it in steps if you want.
What is the outward force (caused by the pressure inside the cabin?)
What is the inward force (caused by the pressure outside the cabin?)
What is the net force (mind the direction of the forces, e.g. relative minus signs!)
Do you see why you can take the difference of the pressures to begin with?
 
Hi tbstar! :smile:

(btw, you can use the X2 tag above the reply box to write e7 :wink:)
tbstar said:
I wanted to understand this solution:

F = P x A = 0.45 x 1.013x10e5 x 1200
F= 5.47 x 10e7

Why we are multiplying the difference pressure between the air and the cabin by the pressure at sea level?

Because the question gave you the pressure as multiples of P0, the sea-level pressure.

This is quite usual … pressure in many situations (particularly where people have to breathe) is measured as multiples of "atmospheric pressure", just as acceleration (of an airplane, for example) is often measured as multiples of g. :smile:
 
If you do the steps I told you, you will see that the formula for the force is
F = (p2 - p1) x A
where p1 and p2 are the outside and inside pressure, respectively. If you plug in the numbers,
F = (0.75 p0 - 0.30 p0) x A
Now, just as you can write x2 + x = x(x + 1), you can rewrite
(0.75 p0 - 0.30 p0) = (0.75 - 0.30) p0
so
F = (0.75 - 0.30) p0 A
 
I am so stupid, I didn't even pay attention to the details that's all. But I have been working on physics problems from 5pm to 2pm straight up because I have an exam tomorrow. So thank you very much guys for helping me to understand how stupid I was asking that stupid question.

Cheers
 
Actually it's a very useful question.
IMO it is far more stupid to learn the formulas by heart without understanding them, real physics is also about grasping the physical concepts (and usually, when you have those right, it's also easier to remember the formulas... or derive them when you forget them).

Basically here, all you have to remember is what pressure is (force per area), then by logical steps you can solve the question (it must be F/A then, so we can write F = p A... what is the outward force, what is the inward force and what is the net force - hey, it's the pressure difference that causes it! That makes sense, otherwise we would also have a force when both the cabin and the ouside air were at sea level pressure p0, for example.). Also, it makes it easier to check your answer (for example: the inside pressure is higher than the outside pressure, so you expect an outward force... does your calculation give that as well?)
 

Similar threads

Replies
2
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
11K
  • · Replies 5 ·
Replies
5
Views
18K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K