Calculating Lid Pressure at Different Altitudes

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Homework Help Overview

The problem involves calculating the force required to lift a lid from a box at different altitudes, specifically at sea level and in Denver, where the atmospheric pressure is lower. The box dimensions and internal pressure are provided, and the participants are exploring the implications of pressure differences on the lid's behavior.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between internal and external pressure, questioning how these pressures affect the lid's ability to remain in place. There are attempts to apply the pressure formula, but confusion arises regarding the implications of pressure differences.

Discussion Status

Some participants have offered guidance by prompting others to consider the effects of pressure differences on the lid's behavior. There is an ongoing exploration of the problem, with various interpretations being discussed, particularly regarding the consequences of a higher internal pressure compared to the external pressure.

Contextual Notes

Participants note the lack of experience with practical examples, which may be influencing their understanding of the problem. The discussion also highlights the absence of definitive answers due to the nature of the online homework format.

warrior2014
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Pressure of a lid!

Homework Statement



A lid is put on a box that is 10cm long, 20cm wide and 8cm tall and the box is then evacuated until its inner pressure is 72000 Pa.

1.How much force is required to lift the lid at sea level?

2. How much force is required to lift the lid in Denver on a day when the atmospheric pressure is 67.5 kPa (2/3 the value at sea level)?

Homework Equations



P=F/A

A=L x W


The Attempt at a Solution



I got #1 where I did the following:

A= L x W= 0.1 x 0.2= 0.02m^2

P=F/A
(101325 - 72000)= F/ 0.02
586.5 N= F

I attempted to do #2 as shown below and got both methods wrong:

so first I did: P=F/A
(67500- 72000)= F/0.02
-90N= F (wrong answer)

so then I did: P=F/A
67500= F/0.02
1350N= F (wrong answer again)

I am unsure how to answer this question, so any help is appreciated! It's online homework so there's no given answer either. thanks!
 
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Your first attempt at #2 is along the right lines, you just didn't analyze the result closely enough. Suppose the lid were secured in place with some kind of fastener. If the pressure inside is higher than outside, what would happen when you undid the restraints? If there were no restraints in place when the outside pressure dropped below the inside pressure, what would happen to the excess pressure in the box?
 


so if you undid the restraints then the pressure inside would decrease? I'm still confused on how to solve the problem.
 


Look at the data: where is the pressure higher, inside or outside? What happens to a lid if the pressure inside the container is higher than the outside pressure? Do you have no kitchen experience with boiling milk in a covered pot? :wink:

ehild
 


no kitchen experience at all! but if the pressure inside the container is higher than the outside, wouldn't the lid pop off? I still don't get how this will help me get the question...
 


warrior2014 said:
no kitchen experience at all! but if the pressure inside the container is higher than the outside, wouldn't the lid pop off? I still don't get how this will help me get the question...

Think it through. If the lid pops off by itself, how much force is required to remove the lid?
 


Oh okay I get it. thank-you for all of your help :)!
 

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