Calculating Force Needed to Lift Lid in Denver

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Homework Help Overview

The problem involves calculating the force required to lift a lid from a box that has been evacuated to a specific internal pressure, with consideration of the atmospheric pressure in Denver. The subject area relates to fluid mechanics and pressure differentials.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the internal and external pressure values, with some questioning the accuracy of the pressure readings and their implications for the force calculation.

Discussion Status

There is an ongoing exploration of the pressure values involved, with some participants clarifying and correcting previous statements. The discussion reflects a mix of attempts to understand the implications of the pressure differences without reaching a consensus on the final calculation.

Contextual Notes

Participants are addressing potential confusion over the notation of pressure values and their interpretations, which may affect the calculations. The atmospheric pressure is noted to be lower than typical sea level pressure, which is relevant to the problem.

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Homework Statement


A lid is put on a box that is 14 cm long, 12 cm wide, and 8.0 cm tall and the box is then evacuated until its inner pressure is 9.0 104 Pa.

How much force is required to lift the lid in Denver on a day when the atmospheric pressure is 67.5 kPa (2/3 the value at sea level)?


The Attempt at a Solution



(67500-90000)*.o168
=-378 N

I Keep getting my answer wrong could someone help please
 
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lalahelp said:

Homework Statement


A lid is put on a box that is 14 cm long, 12 cm wide, and 8.0 cm tall and the box is then evacuated until its inner pressure is 9.0 104 Pa.
Can you clarify that pressure value?
 
the pressure value is 90000 pa
 
lalahelp said:
the pressure value is 67500 pa

9.0 104 Pa is 67500 pa ?

Is it supposed to be 9.0x104 Pa ?
 
Yeh I messed up my bad sorry
 
Okay, then your working seems fine. What does it mean if the pressure outside is now less than what the pressure in the box is (or was!).
 

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