How Much Heat Does a Hand Absorb from Hot Water?

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SUMMARY

The discussion focuses on calculating the heat absorbed by a person's hand when 100 grams of water at 100°C is poured onto it, with the water cooling to a final temperature of 37°C. The specific heat capacity of water, which is 4.18 J/g°C, is essential for this calculation. The energy lost by the water can be determined using the formula Q = mcΔT, where Q is the heat absorbed, m is the mass of the water, c is the specific heat capacity, and ΔT is the change in temperature. This results in a definitive calculation of the heat transfer involved in this scenario.

PREREQUISITES
  • Understanding of specific heat capacity
  • Familiarity with the formula Q = mcΔT
  • Basic knowledge of temperature scales
  • Concept of heat transfer
NEXT STEPS
  • Calculate heat transfer using Q = mcΔT with different masses of water
  • Explore the concept of thermal equilibrium in heat transfer
  • Investigate specific heat capacities of other substances
  • Learn about the effects of heat on human skin and tissue
USEFUL FOR

Students studying thermodynamics, physics enthusiasts, and anyone interested in understanding heat transfer principles in practical scenarios.

ozziegolf05
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Homework Statement



How much heat is absorbed by a person’s hand if 100 grams of liquid water at 100°C is poured on his hand? (Assume the final temperature of the water will be normal body temperature of 37°C)


Homework Equations


dont have any


The Attempt at a Solution


dont have one.
 
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Well, you know the temperature change of the water. You also know the specific heat capacity of water. Therefore, you can figure out how much energy has to be lost by that amount of water in order for that temperature change to occur.
 

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