How Much Heat Is Required to Vaporize Water in Homework Problem 2.9?

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SUMMARY

The discussion focuses on calculating the work done by gas and the heat required to vaporize water in a specific homework problem. The work done during the vaporization process is determined to be 533.81 J using the formula W = pV. To find the heat added, the latent heat of vaporization (Lv) of water, which is 2.26 × 106 J/kg, is utilized alongside the mass of water, derived from its density of 1000 kg/m3.

PREREQUISITES
  • Understanding of thermodynamics, specifically the concepts of work and heat transfer.
  • Familiarity with the latent heat of vaporization and its application in phase changes.
  • Knowledge of the ideal gas law and how pressure and volume relate in gas processes.
  • Basic skills in unit conversion, particularly between cm3 and m3.
NEXT STEPS
  • Calculate the mass of water using the formula mass = density × volume.
  • Explore the relationship between pressure, volume, and work in thermodynamic processes.
  • Investigate the implications of latent heat in other phase change scenarios.
  • Learn about the specific heat capacity of water and its role in heating processes.
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone involved in understanding heat transfer and phase changes in fluids.

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Homework Statement

2.9 cm3 of water is boiled at atmospheric
pressure to become 5271.2 cm3 of steam, also
at atmospheric pressure.
Calculate the work done by the gas during
this process. The latent heat of vaporization
of water is 2.26 × 106 J/kg .
Answer in units of J.
(part 2) Find the amount of heat added to the water
to accomplish this process.
Answer in units of J.



Homework Equations

W= pV, Q=mLv




The Attempt at a Solution

Ok SO the awnser to the first part is 533.81 J. What I don't understand is the second part. The equation that I think I use is Q=mass * Lv...but I don't know my mass...
 
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At atmospheric pressure, water has a density of 1000 kg/m3.
 

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