How Much Pressure Is Needed to Inject Water at 1.5g/s Through a Tiny Needle?

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SUMMARY

The discussion focuses on calculating the pressure difference required to inject a solution at a rate of 1.5 g/s through a hypodermic needle measuring 3.2 cm in length and 0.25 mm in diameter. The relevant equation used is V = [(P1-P2)(π*r^4)]/(8*n*L), where P1-P2 represents the pressure difference, r is the radius, n is the viscosity, and L is the length of the needle. The viscosity of water at 20°C is given as 0.0010055 Pa·s. The user seeks assistance in converting the mass flow rate to a volumetric flow rate to proceed with the pressure calculation.

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A patient is given an injection with a hypodermic needle 3.2 cm long and 0.25 mm in diameter. Assuming the solution being injected has the same density and viscosity as water at 20°C, find the pressure difference needed to inject the solution at the rate of 1.5 g/s.

ok I have the equation V = [(P1-P2)(pi*r^4)]/(8*n*L)
(P1-P2)= pressure difference
r= .000125 m
n= .0010055
L= .032 m
I do not know how I am suppose to transform 1.5g/s to m/s because I am unsure of how to transfer grams to meters... once i get that I can find the difference in pressure...

In a similar problem with diameter being .28mm the answer came out to be 320kPa... help?
 
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Pressure energy is converted into kinetic energy.
To convert volume flow into velocity, you can consider:

[tex]\dot{V}= A\cdot v[/tex]
 

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