How much steel is needed to suspend a balloon at 50 ft below sea level?

  • Context: Undergrad 
  • Thread starter Thread starter Don654321
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Discussion Overview

The discussion revolves around calculating the weight of steel required to suspend a balloon filled with air at a depth of 50 feet below sea level in seawater. The focus is on the principles of buoyancy and the relevant physical properties of seawater and steel.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant seeks assistance with a calculation involving the buoyancy of a 12-inch diameter balloon at a specific depth in seawater.
  • Another participant encourages the original poster to attempt the calculation themselves and suggests using the buoyancy equation along with the densities of seawater and steel.
  • A participant provides the densities of seawater (1025 kg/m³) and steel (7850 kg/m³) but expresses uncertainty about which formula to apply.
  • There is a suggestion to use the buoyancy equation without specifying further details or context.

Areas of Agreement / Disagreement

Participants do not appear to have reached a consensus, as there are varying levels of understanding and uncertainty regarding the appropriate formulas and calculations to use.

Contextual Notes

Participants have not fully clarified the assumptions underlying their calculations, such as the effects of pressure at depth or the specific conditions of the balloon's material.

Who May Find This Useful

This discussion may be useful for individuals interested in buoyancy calculations, physics students seeking practical applications of theoretical concepts, or those curious about the properties of materials in different environments.

Don654321
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I need some help with a calculation. I am trying to calculate how much steel in weight would be needed to suspend a ball(essentially a balloon) 12in in diameter full of air at 50 ft below sea level, in sea water. I am not the best at physics and I think I have an idea but wanted a good opinion. Does not have to be exact just a good estimation.
 
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Welcome to PF!

The best way to learn is to learn by doing. So take a shot. Some hints to get you started: do you know the equation for buoyancy? Density of water and steel?
 
seawater=1025 kgm3 Steel = 7850 kgm3 and I am not exactly sure which formula to use?
 

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